Answer:
[tex]\boxed {\boxed {\sf 2,702,840 \ Joules }}[/tex]
Explanation:
The gravitational potential energy can be found using the following formula
[tex]E_p=m*g*h[/tex]
Where m= mass, g= gravitational acceleration, and h = height.
We know the the mass of the woman is 70 kilograms and the height is 3,940 meters
If we assume this parachute is on Earth, then the gravitational acceleration is 9.8 m/s²
[tex]m= 70 \ kg \\h= 3,940 \ m \\g= 9.8 \ m/s^2[/tex]
Substitute the values into the formula.
[tex]E_p= (70 \ kg) (9.8 \ m/s^2)(3,940 \ m)[/tex]
Multiply the first two numbers first.
[tex]E_p=686 \ kg*m/s^2 (3,940 \ m )[/tex]
[tex]E_p=686 \ N (3,940 \ m)[/tex]
Multiply again.
[tex]E_p= 2702840 \ N*m[/tex]
[tex]E_p=2702840 \ J[/tex]
The potential energy of the women is 2,702,840 Joules
