If QT is the perpendicular bisector of PR, find the measure of each.

Answer:
x = 7
y = 12
PQ = QR = 29
Step-by-step explanation:
In ΔPSR , PS = SR (given)
[tex]=> 4x+4=7x-17\\=> 7x-4x=17+4\\=>3x=21\\=>x=\frac{21}{3}=7[/tex]
In ΔPQR , QT is perpendicular bisector of PR. So , PT = RT . As ΔPQR has a perpendicular bisector , it is an isosceles triangle.
So,
,[tex]PQ = RQ\\=>5y-31=2y+5\\=>5y-2y=31+5\\=>3y=36\\=>y=\frac{36}{3} =12[/tex]
Applying the Pythagorean Theorem and the definition of perpendicular bisector, the values of x and y, as well as the measures of each segment in the image are:
Given:
PQ = 5y - 31
PT = 6x - 2y
QR = 2y + 5
PS = 4x + 4
SR = 7x - 17
Find the value of x:
PS = SR (congruent sides)
[tex]4x + 4 = 7x - 17[/tex]
[tex]4x -7x = -4 - 17\\\\-3x = -21[/tex]
x = 7
Find the value of y:
PQ = RQ (since QT is the perpendicular bisector of PR, PT equals TR, therefore, triangles PQT and RQT are congruent).
[tex]5y - 31 = 2y + 5[/tex]
[tex]5y - 2y = 31 + 5\\\\3y = 36\\\\\mathbf{y = 12}[/tex]
Find the length of each side by plugging in the value of x and y:
PQ = 5y - 31 = 5(12) - 31 = 29
PT = TR = 6x - 2y = 6(7) - 2(12) = 18
QR = 2y + 5 = 2(12) + 5 = 29
PS = 4x + 4 = 4(7) + 4 = 32
SR = 7x - 17 = 7(7) - 17 = 32
Find QT using Pythagorean Theorem:
[tex]QT = \sqrt{QR^2 - TR^2} \\\\QT = \sqrt{29^2 - 18^2} \\\\QT = 22.7[/tex]
Therefore, applying the Pythagorean Theorem and the definition of perpendicular bisector, the values of x and y, as well as the measures of each segment in the image are:
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