Step-by-step explanation:
[tex] \frac{ {(2 - b)}^{2} }{{(b - 2)}^{2} } [/tex]
[tex] \frac{(2-b)(2-b)}{(b - 2)(b - 2)} [/tex]
[tex] \frac{4 - 2b - 2b + {b}^{2} }{ {b}^{2} - 2b - 2b + 4 } [/tex]
[tex] \frac{4 - 4b + {b}^{2} }{ {b}^{2} - 4b + 4 } [/tex]
(Rearrange)
[tex] \frac{ {b}^{2} - 4b + 4 }{ {b}^{2} - 4b + 4 } [/tex]
Then eliminate same sign above and below.
since they all have pair, therefore the equation is equal to 1.
(If anybody did any answer please delete this I feel so embarrassed haha)
I hope you understand and let me know whether this helps :)
