Respuesta :
Answer:
C
Explanation:
The period of a pendulum is found by the equation: T = 2pi*sqrt(L/g). Let the original length be L and the original period be T. The length increased by a factor of 4, so it’s new length is 4L. We get that the new period is 2pi*sqrt(4L/g) = 2pi*2sqrt(L/g) = 4pi*sqrt(L/g). We can see that the period increased by a factor of 2 because the original period, T, equals 2pi*sqrt(L/g) and the new period is 4pi*sqrt(L/g) = 2(2pi*sqrt(L/g)) = 2T. Therefore, the new period is 2(1.4) = 2.8
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The new period of the pendulum given that the length increased by a factor of 4 is 2.8 s
Formula for calculating period of pendulum
T = 2π√(L / g)
Where
- T is the period
- L is length
- g is the acceleration due to gravity
How to determine the new period
- Initial period (T₁) = 1.4 s
- Initial length (L₁) = L
- New length (L₂) = 4L
- New period (T₂) =?
T = 2π√(L / g)
Square both side
T² = 4π²L / g
Divide both side by L
T² / L = 4π²/ g
Constant => 4π²/ g
T² / L = constant
Thus,
T²₁ / L₁ = T²₂ / L₂
1.4² / L = T²₂ / 4L
1.96 / L = T²₂ / 4L
Cancel out L
1.96 = T²₂ / 4
Cross multiply
T²₂ = 1.96 × 4
T²₂ = 7.84
Take the square root of both side
T₂ = √7.84
T₂ = 2.8 s
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