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1. Name the pair of congruent sides in the figure below.
A. RT = RS
B. RS = ST
C. No congruent sides
D. RT = ST

2. Find the value of x in the figure below.
A. 6 inches
B. 18 inches
C. 9 inches
D. 12 inches

3. The vertex angle of an isosceles triangle is 50 more than twice the base angles. Find each base angle.
A. The base angles are each 50°
B. The base angles are each 32.5°
C. The base angles are each 100°
D. The base angles are each 30°

4. Solve for x.
A. x = 18
B. x = 4
C. x = 11
D. x = 7

WILL GIVE BRAINLIEST IF I CAN FIGURE IT OUT!! thank you!

1 Name the pair of congruent sides in the figure below A RT RS B RS ST C No congruent sides D RT ST 2 Find the value of x in the figure below A 6 inches B 18 in class=
1 Name the pair of congruent sides in the figure below A RT RS B RS ST C No congruent sides D RT ST 2 Find the value of x in the figure below A 6 inches B 18 in class=
1 Name the pair of congruent sides in the figure below A RT RS B RS ST C No congruent sides D RT ST 2 Find the value of x in the figure below A 6 inches B 18 in class=
1 Name the pair of congruent sides in the figure below A RT RS B RS ST C No congruent sides D RT ST 2 Find the value of x in the figure below A 6 inches B 18 in class=

Respuesta :

Answer:

Note that the sum of the angles in a triangle are 180.

1. B. <R = 180 - 70 -55 = 55. Since <R = <T, then RS = ST

2. D. <J = 180 - 42 -96 = 42 = <K, so JL = KL = 12

3. B. Let the base angle = x. The vertex angle = 2x + 50. The sum of the angles in a triangle is 180, so x + x + 2x + 50 = 4x + 50 = 180 -> 4x = 130 -> x = 32.5.

4. D. Since <S = <Q, RQ = RS. Thus, 2x + 4 = 18 -> 2x = 14 -> x =7

I hope this helps!