Heya!!
For calculate final velocity, lets applicate formula
[tex]\boxed{V=V_o+a*t}[/tex]
Δ Being Δ
V = Final Velocity = ?
Vo = Initial velocity = 4,3 m/s
a = Aceleration = 3 m/s²
t = Time =5 s
⇒ Let's replace according the formula:
[tex]\boxed{V=4,3\ m/s +3\ m/s* 5\ s}[/tex]
⇒ Resolving
[tex]\boxed{V=19,3\ m/s}[/tex]
Result:
The velocity after 5 sec is 19,3 meters per second (m/s)
For calculate distance, lets applicate formula
[tex]\boxed{x=V_o*t+\dfrac{a*t^{2}}{2}}}[/tex]
Δ Being Δ
x = Distance = ?
Vo = Initial velocity = 4,3 m/s
a = Aceleration = 3 m/s²
t = Time =5 s
⇒ Let's replace according the formula:
[tex]\boxed{x=4,3 * 5 +\dfrac{3*5^{2}}{2}}}[/tex]
⇒ Resolving
[tex]\boxed{x = 59 \ m}[/tex]
Result:
The distance is 59 meters.
Good Luck!!
