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Space

Answer:

0.94 mol NaCl

General Formulas and Concepts:

Chemistry - Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

Step 1: Define

55g NaCl

Step 2: Identify Conversions

Molar Mass of Na - 22.99 g/mol

Molar mass of Cl - 35.45 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

Step 3: Covert

[tex]55 \ g \ NaCl(\frac{1 \ mol \ NaCl}{58.44 \ g \ NaCl} )[/tex] = 0.941136 mol NaCl

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

0.941136 mol NaCl ≈ 0.94 mol NaCl

In 55 grams of sodium chloride (NaCl), 0.94 moles of NaCl is present.

What are moles?

Number of moles of any substance is defined as:

n = W / M

Where, W = given mass or weight

M = molar mass

In the question given weight of NaCl is 55 g.

And molar mass of NaCl is 58.44 g/mol

Now we put all these values in the above equation, we will get:

n = 55 / 58.44 = 0.94 mol

Hence, 0.94 mole of NaCl is present in 55g of NaCl.

To know more about moles, do visit below link:

https://brainly.com/question/15374113

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