contestada

How many moles of NH3 can be produced by the reaction of 2.00 g of N2 with 3.00 g H2?
Reaction: N2 (g) + 3 H2(g) + 2NH3 (g)
O 0.143
O 0.0567
O 0.235
O 1.00
O none of the above

Respuesta :

0.285 moles of NH3 will be produced in the reaction.

Mole calculation

To determine the number of moles of a product formed, one must have knowledge of the stoichiometric proportions of the reaction.

In the case of the question, we have that for every 1 mol of N2, 2 mol of NH3 are formed, so it is enough to calculate the amount of mols of N2 present and perform the proportion:

                                    [tex]MM= \frac{m}{mol} \\14g/mol= \frac{2g}{mol} \\\\mol = 0.143[/tex]

Finally, just perform the proportion, so that:

                                              [tex]\frac{1mol}{0.143mol} =\frac{2mol}{xmol}\\\\x = 0.285[/tex]

So, none of the above options are right, since 0.285 moles of NH3 will be produced in the reaction.

Learn more about mole calculation in: brainly.com/question/12104084