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What polynomial has roots of -4, 1, and 6?
x^3 - 3x^2 – 22x + 24
x^3 – x^2 - 26x - 24
x^3 + x^2 – 26x + 24
x^3 + 3x^2 + 14x - 24

Respuesta :

orj
x^3-3x^2-22x+24
the first option is the answer

solution: (x + 4)(x - 1)(x -6) = (x^2 - x + 4x -4)(x - 6)
(x^2 + 3x -4)(x - 6) = x^3 -6x^2 + 3x^2 - 18x - 4x + 24 = x^3 - 3x^2 - 22x + 24

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