What is an equation of the line that passes through the points (6, -7) and (-6, 3))? Put your answer in fully reduced form.

Respuesta :

Answer:

The equation of the line is y = [tex]-\frac{5}{6}[/tex] x - 2

Step-by-step explanation:

The form of the linear function is y = m x + b, where

  • m is the slope
  • b is the y-intercept

The rule of the slope is m =[tex]\frac{y2-y1}{x2-x1}[/tex] , where

  • (x1, y1) and (x2, y2) are two points on the line

∵ The line passes through points (6, -7) and (-6, 3)

∴ x1 = 6 and y1 = -7

∴ x2 = -6 and y2 = 3

→ Substitute them in the rule of the slope above to find it

∵ m = [tex]\frac{3--7}{-6-6}[/tex] = [tex]\frac{3+7}{-12}[/tex] = [tex]\frac{10}{-12}[/tex] = [tex]\frac{5}{-6}[/tex]

m = [tex]-\frac{5}{6}[/tex]

→ Substitute it in the form of the equation above

∴ y = [tex]-\frac{5}{6}[/tex] x + b

→ Substitute x and y in the equation by x1 and y1

∵ x1 = 6 and y1 = -7

∴ -7 = [tex]-\frac{5}{6}[/tex] (6) + b

∴ -7 = -5 + b

→ Add 5 to both sides

∵ -7 + 5 = -5 + 5 + b

-2 = b

→ Substitute the value of b in the equation

∴ y = [tex]-\frac{5}{6}[/tex] x + -2

∴ y = [tex]-\frac{5}{6}[/tex] x - 2

The equation of the line is y = [tex]-\frac{5}{6}[/tex] x - 2