Answer:
The negative solution = x = -4
Step-by-step explanation:
Let the number be = x
The square of number = x²
The difference between the square of a number and 28 = x²-28
Given that the difference of the square of a number and 28 is equal to three times that number.
Thus, the equation becomes
[tex]x^2-28=3x[/tex]
subtract 3x from both sides
[tex]x^2-28-3x=3x-3x[/tex]
[tex]x^2-3x-28=0[/tex]
[tex]\left(x+4\right)\left(x-7\right)=0[/tex]
[tex]x+4=0\quad \mathrm{or}\quad \:x-7=0[/tex]
[tex]x=-4,\:x=7[/tex]
Thus, the negative solution = x = -4
