Answer:
We conclude that the correct option is 'A'.
As I was able to get (6, -6) because I was able to eliminate my y terms first.
Step-by-step explanation:
Given the system of equations
[tex]\begin{bmatrix}-4x-2y=-12\\ 4x+8y=-24\end{bmatrix}[/tex]
solving using the elimination method
[tex]4x+8y=-24[/tex]
[tex]+[/tex]
[tex]\underline{-4x-2y=-12}[/tex]
[tex]6y=-36[/tex]
so
[tex]\begin{bmatrix}-4x-2y=-12\\ 6y=-36\end{bmatrix}[/tex]
solve for y
[tex]6y=-36[/tex]
Divide both sides by 6
[tex]\frac{6y}{6}=\frac{-36}{6}[/tex]
[tex]y=-6[/tex]
[tex]\mathrm{For\:}-4x-2y=-12\mathrm{\:plug\:in\:}y=-6[/tex]
[tex]-4x-2\left(-6\right)=-12[/tex]
[tex]-4x+12=-12[/tex]
[tex]-4x=-24[/tex]
Divide both sides by -4
[tex]\frac{-4x}{-4}=\frac{-24}{-4}[/tex]
[tex]x=6[/tex]
Thus, the solutions are:
[tex]x=6,\:y=-6[/tex]
Therefore, we conclude that the correct option is 'A'.
As I was able to get (6, -6) because I was able to eliminate my y terms first.
