Describe how to evaluate the expression 3^2 + (21 - 9) X 6÷2. Can someone help me out, please? I'm having trouble, and my teacher isn't responding to my messages.

Respuesta :

Answer:

[tex]3^2+\left(21-9\right)\times \:6\div \:2=45[/tex]

Step-by-step explanation:

Given the expression

[tex]3^2\:+\:\left(21\:-\:9\right)\:\times \:6\div 2[/tex]

Follow the PEMDAS order of operations

[tex]3^2\:+\:\left(21\:-\:9\right)\:\times \:6\div 2[/tex]

calculate within parentheses  [tex]\:(21-9)=12[/tex]

[tex]=3^2+12\times \:6\div \:2[/tex]

calculate exponents  [tex]3^2=9[/tex]

[tex]=9+12\times \:6\div \:2[/tex]

Multiply and divide (left to right)

[tex]=9+36[/tex]

Add and subtract (left to right)  [tex]12\times \:\:6\div \:\:2=36[/tex]

[tex]=45[/tex]

Thus,

[tex]3^2+\left(21-9\right)\times \:6\div \:2=45[/tex]