Answer:
Molarity = 0.014 M
Explanation:
Given data:
Volume of H₂SO₄ = 24.9 mL
Molarity of H₂SO₄ = ?
Volume of LiOH = 20.5 mL
Molarity of LiOH = 0.0365 M
Solution:
Volume of LiOH:
20.5 mL × 1 L /1000 mL
0.0205L
Volume of H₂SO₄:
24.9 mL × 1 L /1000 mL
0.0249 L
Chemical equation:
H₂SO₄ + 2LiOH → Li₂SO₄ + 2H₂O
Number of moles of LiOH:
Molarity = number of moles / volume in L
0.0365 M = number of moles / 0.0205L
n = 0.0365 M × 0.0205L
n = 0.0365 mol/L × 0.0205L
n = 0.0007 mol
now we will compare the moles of LiOH and H₂SO₄
LiOH : H₂SO₄
2 : 1
0.0007 : 1/2×0.0007 = 0.00035 mol
Molarity of H₂SO₄:
Molarity = number of moles / volume in L
Molarity = 0.00035 mol / 0.0249 L
Molarity = 0.014 M
