Answer:
a) Epot = 17658 [J]
b) v = 76.72 [m/s]
Explanation:
Potential energy is defined as the product of mass by gravity by height.
[tex]E_{pot}=m*g*h\\[/tex]
where:
Epot = potential energy [J]
m = mass = 6 [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 300 [m]
Now replacing:
[tex]E_{pot}=6*9.81*300\\E_{pot} = 17658 [J][/tex]
b)
The energy is conserved, that is, the potential energy is converted into kinetic energy as the car descends.
[tex]E_{k}=\frac{1}{2} *m*v^{2}[/tex]
where:
v = velocity = 2 [m/s]
[tex]17658 = \frac{1}{2} *6*v^{2} \\v=\sqrt{5886}\\v=76.72 [m/s][/tex]
