Explanation:
[tex]\boxed{\sf{K.E = \dfrac{1}{2} \times m \times v^2}}[/tex]
- Here, K . E or Kinetic Energy is given as 14 J
- Here, mass is 17 kg
Let's Do!
[tex]\boxed{\sf{14 = \dfrac{1}{2} \times 17 \times v^2}}[/tex]
[tex]\boxed{\sf{\dfrac{14 \times 2}{17} = v^2}}[/tex]
[tex]\boxed{\sf{ \sqrt{\dfrac{14 \times 2}{17}}= v}}[/tex]
So, 1.283 m/s is the required answer.
