Answer:
pH = 14.05.
Explanation:
Hello!
In this case, since barium hydroxide ionizes according to the following equation:
[tex]Ba(OH)\rightarrow Ba^{2+}+2OH^-[/tex]
We can compute the concentration of hydroxyl ions based on:
[tex][OH^-]=0.606\frac{molBa(OH)_2}{L}*\frac{2molOH^-}{1molBa(OH)_2} =1.21M[/tex]
Next we compute the pOH:
[tex]pOH=-log([OH^-])=-log(1.12)=-0.0500[/tex]
Thus the pH is:
[tex]pH=14-pOH=14+0.05\\\\pH=14.05[/tex]
Which means it is very concentrated basic solution.
Best regards!
