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  • 07-12-2020
  • Mathematics
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v1 - 2 sin cos 0 = cos 0 - sin​

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  • 07-12-2020

[tex] \sqrt{1 - 2sin θ \cosθ } = \sqrt{ {sin}^{2} θ + {cos}^{2}θ - 2 sinθcosθ } = \sqrt{ {(cosθ - sinθ) }^{2} } = cosθ - sinθ[/tex]

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