Answer:
Given:-
Volume of a basketball=[tex]\sf 5600cm^3 [/tex]
To find:-
Radius
Solution:-
- We know basketball is a sphere
- We know that in a sphere
[tex]{\boxed {\sf Volume=\dfrac {4}{3}\pi r^3 }}[/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf \dfrac {4}{3}\times \dfrac {22}{7}\times r^3=5600 [/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf \dfrac {88}{21}r^3=5600 [/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf r^3=5600\times \dfrac {21}{88}[/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf r^3=\dfrac {5600×21}{88}[/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf r^3=\dfrac{117600}{88}[/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf r^3=1336.36 [/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf r=\sqrt [3]{1336.33}[/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf r=11.01 [/tex]
[tex]\qquad{:}\longrightarrow[/tex][tex]\sf r=11cm (Approx)[/tex]
[tex]\therefore\sf radius \:of \;basketball\:is\:11cm.[/tex]
