Answer:
I think your forgot to add some parts of this question, because you can't do anything with this except simplify it down a little maybe. But, I will provide the simplified version of this.
[tex]\frac{x-4}{x^2-2x}+\frac{4}{x^2-4}[/tex]
= [tex]\frac{x-4}{x\left(x-2\right)}+\frac{4}{x^2-4}[/tex]
= [tex]\frac{x-4}{x\left(x-2\right)}+\frac{4}{\left(x+2\right)\left(x-2\right)}[/tex]
= [tex]\frac{\left(x-4\right)\left(x+2\right)}{x\left(x-2\right)\left(x+2\right)}+\frac{4x}{\left(x+2\right)\left(x-2\right)x}[/tex]
= [tex]\frac{\left(x-4\right)\left(x+2\right)+4x}{x\left(x-2\right)\left(x+2\right)}[/tex]
= [tex]\frac{x+4}{x\left(x+2\right)}[/tex]
Step-by-step explanation:
Hope this helped!
