If we make s = Senior tickets,
11s+1s
to find the values of c and s,w
If we express s in terms of c on t
s=21-2c
replacing this value on the first equation, we obtain
[tex]11(21-2c)+4c=123\\11.21-22c+4c=123\\231-18c=123\\231=123+18c\\231-123=18c\\108=18c\\c=\frac{108}{18} \\c=6[/tex]
Placing c=6 on s=21-2c, we have
[tex]s=21-2(6)\\s=21-12\\s=9[/tex]
Thus the senior ticket costs $9 and the child ticket cost $6
PLEASE MARK ME AS BRAINLIEST