Explanation:
length of pipe= 32 ft
wavelength of wave λ= 8.8 m
let f be frequency
we know velocity of wave v=λf
therefore, f=v/λ = 346/8.8 = 39.31 per second or hertz
time period = 1/f = 1/39.31 = 0.02543 seconds
The frequency of this sound will be 39.31-sec⁻¹or Hz. While the time period will be 0.02543 sec.
Frequency is defined as the number of repetitions of waves occurring in 1 second. Frequency is also defined as the number of cycles completed in 1 second. SI unit of frequency is Hz.
The given data in the problem is;
L is the length of pipe= 32 ft
λ is the wavelength of wave= 8.8 m
f is the frequency=?
T is the time period=?
The frequency is fine as the ratio of the speed of wave and wavelength.,
[tex]\rm f= \frac{v}{\lambda} \\\\ \rm f= \frac{346}{8.8}\\\\ \rm f= 39.31 \ Hz[/tex]
The time period is guven as the inverse of the time period.
[tex]\rm T = \frac{1}{f} \\\\ \rm T = \frac{1}{39.31} \\\\ \rm T = 0.02543\ sec[/tex]
Hence the frequency of this sound will be 39.31-sec⁻¹or Hz. While the time period will be 0.02543 sec.
To learn more about the frequency reference to the link;
https://brainly.com/question/14926605
