Answer:
V₂ = 252 cm³
Step-by-step explanation:
Charles's law = If the pressure is held constant, the volume of a gas varies directly with the temperature measured on the Kelvin scale.
Mathematically, [tex]V=kT[/tex]
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
We have, V₁ = 192 cm³, T₁ = 112 K, T₂ = 147 cm³, V₂ = ?
Using the above relation of Charles's law :
[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{192\times 147}{112}\\\\V_2=252\ cm^3[/tex]
So, the new temperature is 252 cm³.
