Respuesta :
Explanation:
It is given that,
A jogger runs 300 m due west and then turns and runs 500 m due south
(a) Total distance = total path covered
Distance = 500 m + 300 m
= 800 m
(b) Total displacement = shortest path covered
[tex]D=\sqrt{500^2+300^2} \\\\=583.09 m[/tex]
(c) Speed = distance/time
[tex]s=\dfrac{800\ m}{135\ s}\\\\=5.92\ m/s[/tex]
Velocity = total displacement/total time
[tex]v=\dfrac{583.09\ m}{135\ s}\\\\=4.31\ m/s[/tex]
Hence, this is the required solution.
a) The total distance that she ran is 800m.
b) Her total displacement is 583.09 m
c) Her speed= 5.92 m/s and Velocity= 4.31 m/s
Firstly, let's write the given condition:
A jogger runs 300 m due west and then turns and runs 500 m due south
To find: a) Total distance
b) Total displacement
c) Speed and velocity
Let's solve the question:
(a) Total distance = total path covered
Distance = 500 m + 300 m = 800 m
(b) Total displacement = shortest path covered
For this type of question in which direction is mentioned, so we can use the displacement formula as:
[tex]D=\sqrt{x^{2} +y^2}[/tex]
D=[tex]\sqrt{{(500)}^{2}+{(300)^2}[/tex]= [tex]\sqrt{250000+90000} =\sqrt{340000} =583.09m[/tex]
(c) Speed = distance/time
[tex]s=\frac{d}{t} =\frac{800 m}{135 s} =5.92 m/s[/tex]
where d= distance and t=time
Velocity = total displacement/total time
[tex]v=\frac{d}{t} =\frac{583.09 m}{135 s} =4.31 m/s[/tex]
where d= displacement and t=time
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