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A triangle has a base of x^1/2
m and a height of x^1/3 m. If the area of the triangle is 16 m². what are the base and height of the triangle?

A triangle has a base of x12 m and a height of x13 m If the area of the triangle is 16 m what are the base and height of the triangle class=

Respuesta :

Answer:

Base = 8 m

Height = 4 m

Step-by-step explanation:

Area of triangle

[tex] = \frac{1}{2} \times base \times height \\ \\ 16 \times 2= {x}^{ \frac{1}{2} } \times {x}^{ \frac{1}{3} } \\ \\ 32 = {x}^{ \frac{5}{6} } \\ \\ {2}^{5} = {x}^{ \frac{5}{6} } \\ \\ ({2}^{2})^{ \frac{6}{5} } = x \\ \\ x = {2}^{5 \times \frac{6}{5} } \\ \\ x = {2}^{6} \\ \\ base = {x}^{ \frac{1}{2} } = {({2}^{6})}^{ \frac{1}{2} } \\ \\ base = {2}^{3} \\ \\ base = 8 \: m \\ \\ \\ height = {x}^{ \frac{1}{3} } = {({2}^{6})}^{ \frac{1}{3} } \\ \\ height= {2}^{2} \\ \\ height = 4 \: m[/tex]