Respuesta :
Answer:
General equation for a double-displacement reaction:
AB + CD --> AC + BD
• sodium chloride – NaCl copper sulfate – CuSO₄
NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂
The products formed are sodium sulfate and copper (II) chloride.
Copper (II) chloride forms a blue colored solution.
• sodium hydroxide – NaOH copper sulfate – CuSO₄
NaOH + CuSO₄ --> Na₂SO₄ + Cu(OH)₂
The products formed are sodium sulfate and copper (II) hydroxide.
Copper (II) hydroxide forms a blue colored solution.
• sodium phosphate – Na₂HPO₂ copper sulfate – CuSO₄
Na₂HPO₄ + CuSO₄ --> Na₂SO₄ + CuHPO₄
The products formed are sodium sulfate and copper (II) hydrogen phosphate.
Copper (II) hydrogen phosphate forms a blue colored solution.
• sodium chloride – NaCl silver nitrate – AgNO₃
NaCl + AgNO₃--> AgCl + NaNO₃
The products formed are silver chloride and sodium nitrate.
Silver chloride forms a white precipitate.
• sodium hydroxide – NaOH silver nitrate – AgNO₃
NaOH + AgNO₃ --> NaNO₃ + AgOH
The products formed are silver hydroxide and sodium nitrate.
Silver hydroxide forms a white precipitate.
• sodium phosphate – Na₂HPO₄ silver nitrate – AgNO₃
Na₂HPO₄ + AgNO₃ --> NaNO₃ + Ag₂HPO₄
The products formed are sodium nitrate and silver hydrogen phosphate.
Silver hydrogen phosphate forms a colorless solution.
Explanation:
The two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate are copper(II) phosphate and sodium chloride.
The empirical formula of the copper phosphate =[tex]Cu_3P_2O_8[/tex]
The empirical formula of the sodium chloride = [tex]NaCl[/tex]
Explanation:
- The reaction taking place between copper(II) chloride and sodium phosphate is a double displace reaction and precipitation reaction.
- Double displacement is a type of chemical reaction in which ions of two compounds are exchanged to give new products.
- The precipitation reaction is a reaction in which a solid insoluble product is formed by the reaction of two different aqueous solutions of salt.
- When solutions of copper(II) chloride and sodium phosphate are allowed to react they give a solid precipitate of copper(II) phosphate and an aqueous solution of sodium chloride.
[tex]3CuCl_2(aq)+2Na_3PO_4(aq)\rightarrow Cu_3(PO_4)_2(s)+ 6NaCl(aq)[/tex]
- The empirical formula is the simple whole-number ratio of atoms of the different elements present in the molecule of the compound.
Charge on the copper(II) ion = +2
Charge on the phosphate ion = -3
- The molecular formula of the copper phosphate = [tex]Cu_3(PO_4)_2[/tex]
The ratio of a number of copper, phosphorus, and oxygen atoms:
[tex]Cu:P:O=3:2:8= 3:2:8[/tex]
The empirical formula of the copper phosphate =[tex]Cu_3P_2O_8[/tex]
Charge on the sodium ion = +1
Charge on the chloride ion = -1
- The molecular formula of the sodium chloride =[tex]NaCl[/tex]
The ratio of a number of sodium and chlorine atoms:
[tex]Na:Cl=1:1=1:1[/tex]
The empirical formula of the sodium chloride = [tex]NaCl[/tex]
The two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate are copper(II) phosphate and sodium chloride.
Learn more about empirical formula here:
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