Respuesta :

23 to the 3 because I just took it

Radius of the circumscribed circle of triangle XYZ = 12.08

  • We are given that;

XY = 24

XZ = 22

JQ  =5

From the diagram we are given, we can see that; XJ = JY

Thus; XJ = JY = XY/2

XJ = JY = 22/2 = 11

  • Now, point Q is clearly the centroid of the triangle XYZ as all the perpendicular lines drawn from the midpoints of the three sides meet there.

  • This means that XQ =QZ = QY will be the radius of the circumscribed circle.

Since we know JQ and XJ, let us consider triangle XJQ.

Using Pythagoras theorem;

(XQ)² = (XJ)² + (JQ)²

(XQ)² = 11² + 5²

(XQ)² = 146

XQ = √146

XQ = 12.08

Read more at; https://brainly.com/question/15605172

Otras preguntas