The measure of angles from the given diagram is
∠BOD=108°
∠BAC=72°
Given :
From the given diagram , the angles
[tex]<B=4x-16\\<BCA=5x+7[/tex]
Given triangle is an isosceles triangle
∠A=∠BCA
[tex]<A = 5x+7[/tex]
sum of interior angles in a triangle is 180 degrees
[tex]<A+<B+<BCA= 180\\5x+7+4x-16+5x+7=180\\\\14x+7-16+7=180\\14x-2=180\\14x=182\\\frac{14x}{14}=\frac{182}{14}\\x=13[/tex]
substitute the value of x and find out the remaining angles
[tex]<B=4x-16\\\\<B=4(13)-16=36\\<BCA=5(13)+7=72\\\\<A= 72[/tex]
Angle BCA and angle BCD are linear pair of angles
[tex]<BCA =72\\<BCD= 180-<BCA\\<BCD=180-72\\<BCD=108[/tex]
<BAC= 72 degrees
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