1.643 g mass of acid has been dissolved
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
[tex]\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}[/tex]
Where
M = Molarity
n = number of moles of solute
V = Volume of solution
Molarity of HCl solution = 0.3 M
Volume of HCl solution = 150 ml=0.15 L
So moles of HCl :
[tex]\tt n=M\times V\\\\n=0.3\times 0.15\\\\n=0.045[/tex]
mass of HCl (MW=36.5 g/mol) :
[tex]\tt mass=moles\times MW\\\\mass=0.045\times 36.5\\\\mass=1.643~g[/tex]
