Respuesta :

absor201

Answer:

f(0)= 7.071

Step-by-step explanation:

We are given: [tex]f(x)=2(x)^2+5\sqrt{(x+2)}[/tex]

We need to find f(0)

For finding f(0) put x=0

[tex]f(x)=2(x)^2+5\sqrt{(x+2)}\\Put \ x=0\\f(0)=2(0)^2+5\sqrt{0+2} \\f(0)=2(0)^2+5\sqrt{2}\\f(0)=0+5\sqrt{2}\\f(0)=5(1.4142)\\f(0)=7.071\\[/tex]

So, we get f(0)= 7.071
your answer would be 7.07
since one is closer to 0 then 10, you keep the 7 the same

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