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Silver nitrate and magnesium chloride react according to the following equation:
2AgNO3(aq) + MgCl2(aq) — 2AgCl(s) + Mg(NO3)2(aq)
What volume (in ml) of 0.247M MgCl2(aq) is required to react with 63.2 mL of 0.192M AgNO3(aq)?

Respuesta :

G17Omen

Answer:

V=24,3mL

Explanation:

1)n(AgNO3)=Cm*V=0.063l*0.192M=0.012

2)n(AgNO3)/2=n(MgCl2) => MgCl2=0.012/2=0.006

3)V(MgCl2)=n/Cm=0.006/0.247=0.0243L=24,3ml

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