If StartFraction 1 Over 64 EndFraction = 4 Superscript 2 s minus 1 Baseline times 16 Superscript 2 s + 2, what is the value of s? –1 0 1 no solution

Respuesta :

Answer:

A. -1

Step-by-step explanation:

The value of s in the given expression is; -1

How to simplify Algebraic Expressions?

We are given the expression;

¹/₆₄ = 4^(2s - 1)) * 16^(2s + 2)

This can be simplified to;

4⁻³ = 4^(2s - 1)) * 4^(2(2s + 2))

From laws of exponents we have;

4⁻³ = 4^(2s - 1 + 4s + 4)

4⁻³ = 4^(6s + 3)

From power rule in exponents;

-3 = 6s + 3

-6s = 3 + 3

s = -6/6

s = -1

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