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Which values of x and y would make the following expression represent a real number? (4 + 5i)(x + yi) x = 4, y = 5 x = –4, y = 0 x = 4, y = –5 x = 0, y = 5

Respuesta :

Answer:

C

Step-by-step explanation:

The expression gives a real number as an outcome when x = 4, and y = -5.

Which values of x and y will make the outcome a real number?

Here, you need to remember that the product between a complex number and its complex conjugate is always a real number.

So we only need to define x and y to be such that the second number is the complex conjugate of the first one.

Remember that for a complex number:

[tex]z = a + b*i[/tex]

The complex conjugate is:

[tex]z^* = a - b*i[/tex]

Then the values of x is 4, and the value of y is -5, then we will get:

[tex](4 + 5i)*(4 - 5i) = 16 + 20i - 20i (5)*(-5)*i^2 = 16 + 25 = 41[/tex]

If you want to learn more about complex numbers:

https://brainly.com/question/10662770

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