RaymondJedlicka
contestada

As an Acapulco cliff diver drops into the water from a height of 46 m, his gravitational potential energy decreases by 25,000 J. What is the diver’s weight in newtons?

Respuesta :

mcruz26

Answer:

GPE = m*g*h.

so 25000 J = m * 9.81m/s^2 * 46m

implying the diver's mass is 55.4 kg. precisely what you got.

and from there his/her weight is m*g, which is 55.4kg * 9.81m/s^2 = 543.5 N

Explanation:

snehashish65

At any instant, the potential energy is equal to the product of the weight of an object and the height of an object. So, the required weight of the diver is 543.47 N.

What is potential energy?

The energy possessed by an object by virtue of its position is known as potential energy.

Given data -

The height from the surface of the water is, h = 46 m.

The magnitude of gravitational potential energy is, U = 25,000 J.

The mathematical expression for the gravitational potential energy of the diver is given as,

U = mgh

here,

g is the gravitational acceleration.

m is the mass of diver

And the weight of diver is given as,

W = mg

Then, the potential energy is also expressed as,

U = W × h

Solving as,

25,000 = W × 46

W = 25,000/46

W = 543.47 N

Thus, we can conclude that the weight of diver is 543.47 N.

Learn more about the potential energy here:

https://brainly.com/question/2128880

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