Firstly , Let Rebecca age be R and Steve age be S
Steve is 6 years younger than twice Rebecca age
Since steve is younger, then we will be using subtraction as the order of operation
Since Rebecca age is twice
Then, R x 2
=2R
Steve is 6 years younger than twice of Rebecca age
Mathematically ,
[tex]S=-2R - 6[/tex] ---------------- equation 1
the sum of Steven and Rebecca age is 30
[tex]R+S =30[/tex]------------------ equation 2
Solve equation 1 and equation 2 simultaneously
[tex]S=2R-6\\S+R=30[/tex]
Substitute [tex]S=2R-6[/tex] into equation 2
[tex]2R-6+R=30[/tex]
Collect like terms
[tex]2R+R=30-6[/tex]
[tex]3R=36[/tex]
Divide both sides by R
[tex]\frac{3R}{3} =\frac{36}{3\\} \\R=12[/tex]
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