Hey There!
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Answer:
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DATA:
Range = R = 20 km = 20 000m
Initial Velocity = [tex]V_i[/tex] = 500 m/s
Angle = θ(theta) = ?
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The range of projectile is given by,
[tex]R = \frac{V_i^2}{g}xSin2(theta)[/tex]
Substitute the variables,
[tex]20000 = \frac{500^2}{10} x Sin2(theta)\\\\\frac{200000}{250000} = Sin2(theta)\\\\\frac{4}{5} = Sin2(theta)\\\\Sin(theta) = \frac{4}{2x5}\\\\Sin(theta) = \frac{4}{10}\\\\Sin(theta) = \frac{2}{5} \\\\theta = Sin^{-1}(\frac{2}{5})\\\\theta(angle) = 23.57^0[/tex]
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Best Regards
'Borz'
