Hey There!
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Answer:
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Projectile Motion:
The motion in which a body has constant horizontal component of velocity
but changing vertical component of velocity is called projectile motion. Every projectile body has PROJECTILE MOTION.
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VERTICAL VELOCITY:
The Vertical Velocity will decrease during upward motion and increase during downward motion, by the factor,
[tex]V_f = V_iSin(theta) - gt (Upward Motion)\\\\V_f = V_iSin(theta) + gt (Downward Motion)[/tex]
Where,
Vf = final velocity
Vi = initial velocity
Theta θ is the angle at which projectile is fired
g is acceleration due to gravity
t is time
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B) HORIZONTAL VELOCITY:
HORIZONTAL VELOCITY remains constant. According to Newton's 1st Law object in motion stays in motion until a force acts on it. There are no forces acting on a projectile in the horizontal direction (neglecting air resistance), therefore the velocity is constant.
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Question 19:
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DATA:
Angle = θ(theta) = 30
Initial Velocity = [tex]V_0 = 150 ms^{-1}[/tex]
g = 10 m/s^2
Time taken to reach maximum height = T = ?
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SOLUTION:
The time taken by the projectile to reach the maximum height is given by,
[tex]T = \frac{V_0Sin(theta)}{g}\\\\T = \frac{150Sin(30)}{10}\\\\T = \frac{150x0.5}{10}\\\\T = \frac{75}{10}\\\\T = 7.5 seconds[/tex]
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Best Regards
'Borz'
