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The volume of a scuba tank is 10.0 L. It contains a mixture of nitrogen and oxygen at 290.0 atm.
What volume of this mixture could the tank supply to a diver at 2.40 atm?
Write out the answer

Respuesta :

semont22

Answer:

each gas in the mixture add to give the total pressure (Ptot = P1 + P2 + P3 + ...) 1. ... After mixing, there will be the same number of moles of each gas, at the same T, just in a different volume. .OOL ... Pe=1697 atm P = 174_ atm. (1.000. ... Oxygen is pumped into a tank to supply breathing air for scuba diving, until the gas

Explanation:

Cricetus

The volume of the mixture will be "1208.33 L". A further solution is provided below.

The given values are:

Volume of scuba tank,

  • V₁ = 10 L

Pressure,

  • P₁ = 290 atm
  • P₂ = 2.40 atm

According to the Boyle's Law,

→ [tex]P_1V_1=P_2V_2[/tex]

or,

→      [tex]V_2=\frac{P_1V_1}{P_2}[/tex]

By putting the given values, we get

→           [tex]=\frac{290\times 10}{2.40}[/tex]

→           [tex]= \frac{2900}{2.40}[/tex]

→           [tex]= 1208.33 \ L[/tex]

Thus the above answer is correct.

Learn more about volume of mixture here:

https://brainly.com/question/3841593

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