Answer:
[tex]\boxed{\frac{23}{3} ~in}[/tex] or [tex]\boxed{7,7~in}[/tex]
.
Step-by-step explanation:
Suppose, the first side is a, the second side is b, and the third side is c. So:
→ a = s - 4
→ b = s
→ c = (s - 4) + 3
→ a + b + c = 15
First step, find the value of s
a + b + c = 15
(s - 4) + s + (s - 4) + 3 = 15
3s - 5 = 15
3s = 15 + 5
3s = 20
[tex]s = \frac{20}{3}[/tex]
So, the third side is
c = (s - 3) + 4
c = s + 1
c = [tex]\frac{20}{3} + 1[/tex]
[tex]c = \frac{23}{3}[/tex]
.
Happy to help :)
