Answer:
- The center = (a, b) = (6, -6)
Step-by-step explanation:
Given the equation
[tex]x^2\:+\:y^2\:-\:12x\:+\:12y\:+\:23\:=\:0[/tex]
We know that a circle equation with a radius 'r', centered at (a, b)
[tex]\left(x-a\right)^2+\left(y-b\right)^2=r^2[/tex]
Rewriting [tex]x^2\:+\:y^2\:-\:12x\:+\:12y\:+\:23\:=\:0[/tex] in the form of the standard circle equation
[tex]\left(x-6\right)^2+\left(y-\left(-6\right)\right)^2=7^2[/tex]
Thus,
- The center = (a, b) = (6, -6)
