P Ar = 1.5
P Xe = 0.5
P tot = 2 atm
Further explanation
Dalton's law of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of the component gases
Can be formulated:
P tot = P1 + P2 + P3 ....
The partial pressure is the pressure of each gas in a mixture
3 L Argon , P = 1 atm and 1 L Xe, P=1 atm⇒assume T = 273 K
mol Argon :
[tex]\tt n_{Ar}=\dfrac{PV}{RT}=\dfrac{1\times 3}{0.082\times 273}=0.134[/tex]
mol Xenon :
[tex]\tt n_{Xe}=\dfrac{1\times 1}{0.082\times 273}=0.045[/tex]
[tex]\tt P_{Ar}=\dfrac{nRT}{V}=\dfrac{0.134.0.082.273}{2}=1.5[/tex]
[tex]\tt P_{Xe}=\dfrac{nRT}{V}=\dfrac{0.045.0.082.273}{2}=0.5[/tex]
P tot = 1.5 + 0.5 = 2 atm
