goldennnjoyyy
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Pleasee help(GIVING BRAINILEST) Tyra's family is spending the afternoon in Millersville. They plan to see a movie and then explore the town. The movie will cost the family $36, and parking costs $4 per hour.
How long will the family be able to spend in Millersville if they want to spend less than $60 and they don’t have any other expenses?

Follow the steps to answer this question.

1. Write an inequality that shows that Tyra's family spends less than their limit. Explain how you wrote the inequality, and define any variables used. (2 pts)

Write your answer in the space below.










2. Solve your inequality. Show your work. What does your solution mean? (3 pts)

Write your answer in the space below.

Respuesta :

ducklin
Not exactly sure if I’m right but

1. $56 < $60



2. $60 - $36 = $24/4 hours = 6.

36+24 = 60, we want to use LESS than 60 so we use see how much it’ll take to spend 5 hours for parking.

5 x $4 = $20.

$36 + $20 = $56


I’m not exactly sure though...



martelottebeatr

Answer: 36+4h=60

36+4h-36=60-36

4h=24

4h÷4=24÷4

h=6

So, after the move they can spend 6 hours there. (6×4=24, 24+36=60, they will spend $60 if they spend 6 hours there, $56 if they spend 5 hours there and don't want to spend $60).

Step-by-step explanation:

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