Answer:
[tex]\Delta S=51.1\frac{J}{K}[/tex]
Explanation:
Hello!
In this case, since the entropy and enthalpy are related via the following equation for any process:
[tex]\Delta S=\frac{m\Delta H}{T}[/tex]
As this problem relates the enthalpy and entropy of fusion, given the mass, melting temperature and heat of fusion, we compute the change in entropy of fusion as shown below:
[tex]\Delta S=\frac{0.0419kg*333,000\frac{J}{kg} }{273.15K}\\\\\Delta S=51.1\frac{J}{K}[/tex]
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