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An atom in the ground state absorbs a photon, then emits a photon with a wavelength of 1240 nm. What conclusion can you draw about the energy of the photon that was absorbed

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Answer:

Energy of 1eV is absorbed to move from n=2 to n=3

Explanation:

Since;

E =hc/λ

h= Planks's constant = 6.6 * 10^-34 Js

c= speed of light = 3 * 10^8 ms-1

λ = wavelength = 1240 * 10^-9 m

E =6.6 * 10^-34 * 3 * 10^8/1240 * 10^-9

E = 1.6 * 10^-19 J or 1eV

From the diagram, It is clear that an energy of 1eV is absorbed to move from n=2 to n=3

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