A disk rotates at an angular acceleration of 20 rad/s 2 about its axis. The radius of the disk is 20cm. What is the centripetal acceleration at a point on the edge of the disk when its angular speed is 16 rad/s

Respuesta :

Answer:

The answer is 1280m/s^2

Explanation:

Step one:

given

Angular acceleration of 20 rad/s^2

The radius of the disk is 20cm = 0.2m

angular speed is 16 rad/s

Required

The centripetal acceleration

Step two

The expression for the centripetal acceleration is

[tex]a_c = \frac{ \omega^2}{r}[/tex]

a_c =centripetal acceleration

v =velocity

r =radius

Substituting we have

[tex]a_c = \frac{ 16^2}{0.2}\\\\a_c = \frac{256}{0.2}\\\\ a_c = \1280m/s^2[/tex]