Answer:
0.139 ML⁻¹
Explanation:
The Molarity (M) of a solution is the no of moles (amount) of a solute dissolved in a litre of solution.
M = no of moles / 1 litre of solution of solution
The first step is to calculate the no of moles of Glucose contained in 50g of it
No of moles of glucose = mass/ molar mass of glucose
= 50g / (180.156)g/mol
= 0.27753≅0.278 moles of glucose
Therefore, the molarity of glucose in 2L of solution
= 0.278 moles / 2 lites
= 0.139M/Litre of glucose
= 0.139 ML⁻¹ of glucose
