Question 3
A spherical ball of radius 3 cm is melted and recast into three spherical balls.
The radii of the two balls are 1.5 cm and 2 cm respectively. Determine
the diameter of the third ball.

Respuesta :

Answer:

the diameter of the third ball is 2.5 cm

Step-by-step explanation:

The computation of the diameter of the third ball is as follows:

As we know that

The Volume of a sphere is

= [tex]\frac{4}{3} \pi r^3\\\\\frac{4}{3} \pi (3)^3= \frac{4}{3} \pi (1.5)^3 + \frac{4}{3} \pi (2)^3 + \frac{4}{3} \pi (r)^3[/tex]

(3)^3 = (1.5)^3 + (2)^3 + (r)^3

r^3 = 15.625

r = 2.5 cm

hence, the diameter of the third ball is 2.5 cm

We simply applied the above formula so that the correct value could come

And, the same is to be considered