Each flag is in the shape of an isosceles triangle. To give the fabric support, a ribbon needs to be sewn around the outside edges of the flag. The base of each triangle is 1.25 feet. Eleonore has ordered 500 feet of ribbon and is hoping to make at least 75 flags. What is the maximum length possible for each leg of the triangles? (Round your answer to the nearest tenth)

The maximum length possible for each leg is
feet.

Respuesta :

Answer:

no its 2.7

Step-by-step explanation:

i just took the test its 2.7 duh !

The length of each leg can be found from an expression and an equation that gives the length of ribbon Eleonore has.

  • The maximum length possible for each leg is approximately 2.7 feet.

Reasons:

The shape of the flag = Isosceles triangle

Length of the base of each triangle = 1.25 feet

Length of ribbon available = 500 feet

Number of flags to make = 75 flags

Required:

Maximum possible length for each leg of the triangle

Solution:

Let L represent the length of each leg, we have;

The expression for the perimeter of one flag = 2·L + 1.25

For the 75 flags, the equation is as follows;

75 × (2·L + 1.25) = 500

Which gives;

[tex]\displaystyle 2 \cdot L + 1.25 = \mathbf{\frac{500}{75}} = \frac{20}{3}[/tex]

[tex]\displaystyle L = \frac{\frac{20}{3} - 1.25}{2} = \frac{65}{24} \approx \mathbf{2.708\overline 3}[/tex]

The maximum possible length for each leg, by rounding to the nearest tenth, is L ≈ 2.7 feet

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