Answer:
The magnitude of the centripetal force to make the turn is 3,840 N.
Explanation:
Given;
radius of the cured road, r = 400 m
speed of the car, v = 32 m/s
mass of the car, m = 1500 kg
The magnitude of the centripetal force to make the turn is given as;
[tex]F_c = \frac{mv^2}{r}[/tex]
where;
Fc is the centripetal force
[tex]F_c = \frac{mv^2}{r} \\\\F_c = \frac{(1500)(32)^2}{400}\\\\F_c = 3,840 \ N[/tex]
Therefore, the magnitude of the centripetal force to make the turn is 3,840 N.
