Complete Question
The complete question is shown on the first uploaded image
Answer:
Explanation:
From the question we are told that
The tension is [tex]T = 440 \ N[/tex]
The length of the wire is [tex]l = 0.600 \ m[/tex]
The mass is [tex]m = 5.60 \ g = 0.0056 \ kg[/tex]
Generally the frequency is mathematically represented as
[tex]f = \frac{1}{2l} * \sqrt{\frac{T}{\frac{m}{l} } }[/tex]
=> [tex]f = \frac{1}{2 * 0.600 } * \sqrt{\frac{440}{\frac{0.0056}{0.600} } }[/tex]
=> [tex]f = 181 \ Hz[/tex]
